

How does that work if it’s peer to peer? Doesn’t at least one person need to open ports?


How does that work if it’s peer to peer? Doesn’t at least one person need to open ports?


Do users have to open ports for it to work?


I knew it!


Why say “Your Pixel can now…” when my Pixel can’t? Why not say “Pixel 8 and newer devices can now…”.


I can’t figure out if Free software projects don’t know or don’t care that GitHub is run by Microslop.


Do software keyboards not use the QWERTY layout? Why are we calling hardware keyboards on a phone a QWERTY phone?!


Every question has been answered, pack it up boys.


Do it. I know which OS will run fine on 8G of RAM and which one won’t.


Literally malware tactics from the year 2000.


The updater for the open-source editor Notepad++ has installed malware on WINDOWS PCs. The Linux ecosystem doesn’t allow for this kind of network attack because of signing.


Removed by mod


Bro they couldn’t convince me to upgrade to Windows 8.


I learned about him right before his whole PopOs thing. I couldn’t believe that people would take computing advice from someone who also doesn’t read what’s on the screen in front of him. I expect this from my users I do tech support for, but not someone that bills himself as something as an expert.


It’s insane he ever had a healthy viewership in the first place.


Breach of trust doesn’t have a price tag attached to it. Wake me up when there are any consequences.


Ai isn’t an arrow, you can’t loose it.


The company that’s obsessed with putting popup tutorials in every fucking app and os function? Ambient my ass, stop lying.


How is it possible to be trans and anti-LGBT?
I’ve coded this and I’m a retard. Relative portion from a method:
from urllib.request import urlopen foundrss = False for line in urlopen(self.channelurl): for word in line.split(): if foundrss: if not self.feedurl: self.feedurl = word.split(b'"')[1].decode("utf-8") if 'xml' not in self.feedurl: raise Exception("'xml' not found in feedurl") elif not self.channelname: # feed url is set, extract the channel name that comes soon after if word.startswith(b'content='): # start collecting words self.channelname = [word.split(b'"')[1].decode("utf-8")] if word.count(b'"') == 2: # channel name is a single word self.channelname = self.channelname[0] return else: # we have channelname started, just collect the rest of the words now if b'"' in word: # get text to the left of " self.channelname.append(word.split(b'"')[0].decode("utf-8")) self.channelname = ' '.join(self.channelname) return else: self.channelname.append(word.decode("utf-8")) elif word == b'title="RSS"': foundrss = True